High School

Man A travels 4000 meters in 250 seconds. Man B travels 2000 meters in 120 seconds.

Which man traveled the fastest?

Answer :

Final answer:

After calculating the average speed for both, Man A's average speed is 16 m/s, while Man B's average speed is 16.67 m/s. Therefore, Man B traveled the fastest.

Explanation:

To determine which man traveled the fastest, we need to calculate the average speed of both Man A and Man B. The average speed is calculated by dividing the distance traveled by the time taken to travel that distance.

Calculating Man A's Average Speed:

Distance = 4000 meters

Time = 250 seconds

Average Speed = Distance ÷ Time

Average Speed of Man A = 4000 m ÷ 250 s = 16 m/s

Calculating Man B's Average Speed:

Distance = 2000 meters

Time = 120 seconds

Average Speed = Distance ÷ Time

Average Speed of Man B = 2000 m ÷ 120 s = 16.67 m/s

Since Man B has a higher average speed than Man A, Man B traveled the fastest.

Answer:

Man A: 4,000 m/250 sec = 16 m/sec

Man B: 2,000 m/120 sec = 16.67 m/sec

Man B traveled faster.