Lionel plays trumpet for a minimum of 45 minutes on the days that he practices. If \( x \) is the number of days that Lionel practices and \( y \) is the total number of hours he spends practicing, what would the inequality be?

\[ y \geq \frac{45}{60}x \]

Note: Simplify \(\frac{45}{60}\) to \(\frac{3}{4}\) if needed.

The inequality showing the relationship between Lionel's practice days and practice hours is [tex]y \geq 0.75x[/tex], where x is practice days and y is total hours practiced.

The inequality to represent the relationship between the number of days Lionel practices (x) and the total number of hours he spends practicing (y) is[tex]y \geq 0.75x[/tex]. Since Lionel plays for a minimum of 45 minutes each day he practices, and there are 60 minutes in an hour, each day he practices for 0.75 hours (45 minutes / 60 minutes). Therefore, the inequality shows that for each day he practices (x), he will practice at least 0.75 hours, resulting in the total hours practiced (y) being at least 0.75 times the number of practice days (x).

Twozr Twozr · Answer 2 · 2025-01-28T03:24:21-05:00

The inequality is 0.75x greater than or equal to y

Step-by-step explanation:

Given : Lionel plays trumpet for a minimum of 45 minutes on the days that he practices. If x is the number of days that Lionel practices and y is the total number of hours he spends practicing.

To find : Which inequality represents this situation?

Solution : He plays trumpet for a minimum of 45 minutes

If x is the number of days that Lionel practices then he practices for at least

hours

y is the total number of hours he spends practicing

So, the inequality form is:

i.e, 0.75x is greater than y.