College

One mole of tetraphosphorus decoxide contains:

a. How many molecules?

b. How many grams?

c. How many phosphorus atoms?

d. How many oxygen atoms?

e. How many total atoms?

Answer :

Final answer:

One mole of tetraphosphorus decoxide contains approximately 6.022 x 1023 molecules, weighs 283.88 grams, has 2.409 x 1024 phosphorus atoms, 6.022 x 1024 oxygen atoms, and a total of 8.437 x 1024 atoms. Each aspect can be calculated based on the compound's molecular formula and Avogadro's number.


Explanation:

Understanding Tetraphosphorus Decoxide

Tetraphosphorus decoxide (P4O10) is a chemical compound containing 4 phosphorus atoms and 10 oxygen atoms. When dealing with moles, it is essential to remember that one mole of any substance contains Avogadro's number of molecules, approximately 6.022 x 1023 molecules.

Calculations:

  1. How many molecules?
    One mole of P4O10 contains 6.022 x 1023 molecules.
  2. How many grams?
    The molar mass of tetraphosphorus decoxide can be calculated as follows:
    [tex]\[Molar\ Mass = (4 \times 30.97\,g/mol) + (10 \times 16.00\,g/mol) = 123.88\,g/mol + 160.00\,g/mol = 283.88\,g/mol\][/tex]
    Therefore, one mole of P4O10 weighs 283.88 grams.
  3. How many phosphorus atoms?
    Since one molecule of P4O10 contains 4 phosphorus atoms, one mole of P4O10 contains 4 x 6.022 x 1023 = 2.409 x 1024 phosphorus atoms.
  4. How many oxygen atoms?
    Each molecule contains 10 oxygen atoms, so one mole contains 10 x 6.022 x 1023 = 6.022 x 1024 oxygen atoms.
  5. How many total atoms?
    In one molecule of P4O10, there are 14 total atoms (4 phosphorus + 10 oxygen). Therefore, one mole has 14 x 6.022 x 1023 = 8.437 x 1024 total atoms.

Learn more about tetraphosphorus decoxide here:

https://brainly.com/question/33450831