Answer :
Final answer:
One mole of tetraphosphorus decoxide contains approximately 6.022 x 1023 molecules, weighs 283.88 grams, has 2.409 x 1024 phosphorus atoms, 6.022 x 1024 oxygen atoms, and a total of 8.437 x 1024 atoms. Each aspect can be calculated based on the compound's molecular formula and Avogadro's number.
Explanation:
Understanding Tetraphosphorus Decoxide
Tetraphosphorus decoxide (P4O10) is a chemical compound containing 4 phosphorus atoms and 10 oxygen atoms. When dealing with moles, it is essential to remember that one mole of any substance contains Avogadro's number of molecules, approximately 6.022 x 1023 molecules.
Calculations:
- How many molecules?
One mole of P4O10 contains 6.022 x 1023 molecules. - How many grams?
The molar mass of tetraphosphorus decoxide can be calculated as follows:
[tex]\[Molar\ Mass = (4 \times 30.97\,g/mol) + (10 \times 16.00\,g/mol) = 123.88\,g/mol + 160.00\,g/mol = 283.88\,g/mol\][/tex]
Therefore, one mole of P4O10 weighs 283.88 grams. - How many phosphorus atoms?
Since one molecule of P4O10 contains 4 phosphorus atoms, one mole of P4O10 contains 4 x 6.022 x 1023 = 2.409 x 1024 phosphorus atoms. - How many oxygen atoms?
Each molecule contains 10 oxygen atoms, so one mole contains 10 x 6.022 x 1023 = 6.022 x 1024 oxygen atoms. - How many total atoms?
In one molecule of P4O10, there are 14 total atoms (4 phosphorus + 10 oxygen). Therefore, one mole has 14 x 6.022 x 1023 = 8.437 x 1024 total atoms.
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