Lionel plays the trumpet for a minimum of 45 minutes on the days that he practices. If $ x $ is the number of days that Lionel practices and $ y $ is the total number of hours he spends practicing, which inequality represents this situation?

$ \frac{45}{60}x \le y $

Given : Lionel plays trumpet for a minimum of 45 minutes on the days that he practices. If x is the number of days that Lionel practices and y is the total number of hours he spends practicing.

To find : Which inequality represents this situation?

Solution : He plays trumpet for a minimum of 45 minutes

[tex]45 \text{minutes}=\frac{45}{60}=\frac{3}{4}=0.75\text{hours}[/tex]

If x is the number of days that Lionel practices then he practices for at least

[tex]=0.75x[/tex] hours

y is the total number of hours he spends practicing

So, the inequality form is:

[tex]0.75x\geq y[/tex]

i.e, 0.75x is greater than y.

IDKIMBORED22 IDKIMBORED22 · Answer 2 · 2024-03-11T05:32:21-04:00

IDKIMBORED22 IDKIMBORED22

11-03-2024

Answer:

c

Step-by-step explanation:

on E2020

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Lionel plays the trumpet for a minimum of 45 minutes on the days that he practices. If \( x \) is the number of days that Lionel practices and \( y \) is the total number of hours he spends practicing, which inequality represents this situation?\( \frac{45}{60}x \le y \)

Answer :

Other Questions

Lionel plays the trumpet for a minimum of 45 minutes on the days that he practices. If \( x \) is the number of days that Lionel practices and \( y \) is the total number of hours he spends practicing, which inequality represents this situation?

\( \frac{45}{60}x \le y \)