High School

KTAB is a tablet containing 750 mg of potassium chloride (KCl, MW = 74.5).

How many milliequivalents of KCl are provided in each dose?

Calculate the mEq of KCl provided by the dose.

Answer :

Final answer:

Each dose of KTAB provides approximately 0.01007 milliequivalents (mEq) of KCl.

Explanation:

To calculate the milliequivalents (mEq) of KCl provided in each dose of KTAB, we need to follow these steps:

  1. Convert the given mass of KCl in the tablet to moles.
  2. Calculate the mEq using the molar mass and valence of KCl.

Step 1: Convert the mass of KCl to moles:

Given mass of KCl = 750 mg

Molar mass of KCl = 74.5 g/mol

First, we need to convert the given mass from milligrams to grams:

750 mg = 0.75 g

Next, we can use the molar mass to convert grams of KCl to moles:

Number of moles of KCl = (0.75 g) / (74.5 g/mol) = 0.01007 mol

Step 2: Calculate the mEq of KCl:

The mEq is calculated based on the molar mass and valence of KCl. Since KCl is a 1:1 electrolyte, the valence is 1 for both potassium (K+) and chloride (Cl-) ions.

mEq of KCl = (Number of moles of KCl) x (valence) = 0.01007 mol x 1 = 0.01007 mEq

Therefore, each dose of KTAB provides approximately 0.01007 milliequivalents (mEq) of KCl.

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