Answer :
To solve the equation Karissa was working on, let's go through the steps:
We start from the equation at the point where Karissa left off:
[tex]\[
\frac{1}{2}x + 4 = -\frac{1}{2}x + 4
\][/tex]
Subtract 4 from both sides to isolate the terms with [tex]\( x \)[/tex]:
[tex]\[
\frac{1}{2}x = -\frac{1}{2}x
\][/tex]
To eliminate the fractions and solve for [tex]\( x \)[/tex], let's combine like terms. We'll add [tex]\(\frac{1}{2}x\)[/tex] to both sides to simplify:
[tex]\[
\frac{1}{2}x + \frac{1}{2}x = 0
\][/tex]
This simplifies to:
[tex]\[
x = 0
\][/tex]
Thus, the value of [tex]\( x \)[/tex] that satisfies the equation is [tex]\( \boxed{0} \)[/tex].
We start from the equation at the point where Karissa left off:
[tex]\[
\frac{1}{2}x + 4 = -\frac{1}{2}x + 4
\][/tex]
Subtract 4 from both sides to isolate the terms with [tex]\( x \)[/tex]:
[tex]\[
\frac{1}{2}x = -\frac{1}{2}x
\][/tex]
To eliminate the fractions and solve for [tex]\( x \)[/tex], let's combine like terms. We'll add [tex]\(\frac{1}{2}x\)[/tex] to both sides to simplify:
[tex]\[
\frac{1}{2}x + \frac{1}{2}x = 0
\][/tex]
This simplifies to:
[tex]\[
x = 0
\][/tex]
Thus, the value of [tex]\( x \)[/tex] that satisfies the equation is [tex]\( \boxed{0} \)[/tex].
