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------------------------------------------------ Karissa begins to solve the equation

[tex]\[

\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4)

\][/tex]

Her work is correct and is shown below:

[tex]\[

\begin{array}{c}

\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4) \\

\frac{1}{2} x-7+11=\frac{1}{2} x-x+4 \\

\frac{1}{2} x+4=-\frac{1}{2} x+4

\end{array}

\][/tex]

When she subtracts 4 from both sides, [tex]$\frac{1}{2} x=-\frac{1}{2} x$[/tex] results. What is the value of [tex]$x$[/tex]?

A. [tex]$-1$[/tex]
B. [tex]$-\frac{1}{2}$[/tex]
C. 0
D. [tex]$\frac{1}{2}$[/tex]

Sure! Let's solve the equation step by step to find the value of [tex]$ x $[/tex]:

1. Start with the original equation:
[tex]\[
\frac{1}{2}(x-14) + 11 = \frac{1}{2}x - (x - 4)
\][/tex]

2. Distribute and simplify:
- On the left side: [tex]$\frac{1}{2}(x-14) = \frac{1}{2}x - 7$[/tex]
- On the right side: [tex]$- (x - 4) = -x + 4$[/tex]

So the equation now looks like:
[tex]\[
\frac{1}{2}x - 7 + 11 = \frac{1}{2}x - x + 4
\][/tex]

3. Combine like terms:
- On the left side: [tex]$-7 + 11 = 4$[/tex], so the equation becomes [tex]$\frac{1}{2}x + 4$[/tex]
- On the right side: [tex]$\frac{1}{2}x - x + 4$[/tex] is simplified to [tex]$-\frac{1}{2}x + 4$[/tex]

The equation now is:
[tex]\[
\frac{1}{2}x + 4 = -\frac{1}{2}x + 4
\][/tex]

4. Subtract 4 from both sides:
[tex]\[
\frac{1}{2}x = -\frac{1}{2}x
\][/tex]

5. Add [tex]$\frac{1}{2}x$[/tex] to both sides to combine the [tex]$ x $[/tex] terms:
[tex]\[
\frac{1}{2}x + \frac{1}{2}x = 0
\][/tex]

This simplifies to:
[tex]\[
x = 0
\][/tex]

So, the value of [tex]$ x $[/tex] is [tex]$ 0 $[/tex].