The sinusoidal expression of the function is D(t) = -cos(3t)
A sinusoidal alternating current can be represented by the equation i = I sin ωt, where i is the current at time t and I the maximum current. In a similar way we can write for a sinusoidal alternating voltage v = V sin ωt, where v is the voltage at time t and V the maximum voltage.
here, we have to,
to determine the sinusoidal expression:
When he pushes off, he is 1 m behind the center.
This means that:
Amplitude, a = 1.
But we use, a = -1 because he is behind
The graph has a minimum point at (0,-1) and then intersects its midline at (π/6, 0).
So, the period B is: 2π/B = 4 * π/6 and the vertical shift (d) is 0
Simplify 2π/B = 4 * π/6
2π/B = 2π/3
By comparison, we have:
B = 3
The function is given as:
a cos(Bt) + d
Substitute the calculated values
D(t) = -cos(3t)
Hence, the sinusoidal expression of the function is D(t) = -cos(3t)
Read more about sinusoidal expressions at:
brainly.com/question/16653126
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