John coasts on his skateboard at a speed of 1 m/s. He uses his foot to increase his speed to 3 m/s. If he has a mass of 95 kg, what impulse does he apply?

A. 285 kg•m/s
B. 95 kg•m/s
C. 190 kg•m/s
D. 145 kg•m/s

Question

College

Answer :

Lilmissspicy Lilmissspicy · Answer 1 · 2023-07-15T05:36:29-04:00

Answer:

C

Explanation:

Answer Link

jainveenamrata jainveenamrata · Answer 2 · 2024-07-16T17:33:29-04:00

The value of the impulse of his skateboard will be 190 kg-m/s. Then the correct option is C.

The change in momentum is equal to the product of impact force applied while colliding and the time for that impact.

The impulse is given as the product of the mass and the difference between the final velocity and initial velocity.

Impulse = Mass x (Final velocity - initial velocity)

John coasts on his skateboard at a speed of 1 m/s.

He uses his foot to increase his speed to 3 m/s. If he has a mass of 95 kg.

Then the value of the impulse of his skateboard will be given as,

Impulse = 95 x (3 - 1)

Impulse = 95 x 2

Impulse = 190 kg-m/s

Thus, the value of the impulse of his skateboard will be 190 kg-m/s.

Then the correct option is C.

Learn more about impulse.

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