High School

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------------------------------------------------ In outer space, a constant net force of magnitude 139 N is exerted on a 33.8 kg probe initially at rest. What will be the probe's velocity after 8 seconds due to this force?

A) 3.82 m/s
B) 29.84 m/s
C) 54.43 m/s
D) 107.12 m/s

Answer :

Final answer:

The probe's velocity after 8 seconds due to a force of 139 N will be approximately 29.84 m/s.

Explanation:

To find the velocity of the probe after 8 seconds due to the force of 139 N, we can use Newton's second law of motion.

The formula is F = ma, where F is the force, m is the mass, and a is the acceleration.

First, let's calculate the acceleration:

a = F/m = 139 N / 33.8 kg = 4.11 m/s²

Next, we can use the formula v = u + at to find the final velocity:

v = 0 + 4.11 m/s² * 8 s = 32.9 m/s

Therefore, after 8 seconds, the probe's velocity will be 32.9 m/s, which is approximately 29.84 m/s (option B).

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