Answer :
Final answer:
The Z score associated with an alpha of 0.05 in estimation procedures is approximately 1.96, which captures the central 95% of the standard normal distribution.
Explanation:
In estimation procedures, when dealing with a confidence interval and a significance level (alpha) of 0.05, the corresponding Z score is approximately 1.96. The critical value 1.96 ensures that there is a 0.975 probability to the left and a 0.025 probability in the right tail of the standard normal distribution, which adds up to the central 95% of the distribution. Therefore, for a two-tailed test with an alpha of 0.05, the correct Z score that captures the central 95% of the distribution is approximately 1.96. To find this in a standard normal probability table, you would look for the value that has 0.025 in the tail, because 1 - 0.05 (the alpha) equals 0.95, which is the central probability, and each tail would have half of the remainder, so 0.05/2 = 0.025.
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