Answer :
The 99% confidence interval for the meantime in the population from which the subjects were recruited is approximately (9.24, 13.92) with two decimal places.
To calculate the 99% confidence interval for the meantime in the population from which the subjects were recruited, we can use the following formula:
Confidence Interval = x ± Z * (s / √n)
Where:
x = sample mean
s = sample standard deviation
n = sample size
Z = Z-score for the desired confidence level (99% confidence level corresponds to a Z-score of approximately 2.576)
Given:
x = 11.58
s = 4.37
n = 23
Confidence level = 99% (Z-score = 2.576)
Substituting the values into the formula:
Confidence Interval = 11.58 ± 2.576 * (4.37 / √23)
Calculating the standard error:
Standard Error (SE) = s / √n = 4.37 / √23 ≈ 0.907
Now, we can calculate the confidence interval:
Confidence Interval = 11.58 ± 2.576 * 0.907
Confidence Interval = 11.58 ± 2.34
Lower bound = 11.58 - 2.34 ≈ 9.24
Upper bound = 11.58 + 2.34 ≈ 13.92
Therefore, the 99% confidence interval for the meantime in the population from which the subjects were recruited is approximately (9.24, 13.92) with two decimal places.
Learn more about confidence intervals here:
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