Answer :
Final answer:
Option b, the magnitude of the charge is 4.03 × 10^-8 C and its sign is positive. This is found by using the formula for electric potential due to a point charge, and the positive potential indicates a positive charge.
Explanation:
If the potential due to a point charge is 6.00 × 102 V at a distance of 14.9 m, we can use the formula for electric potential (V) due to a point charge (Q) at a distance (r): V = kQ/r, where k is the Coulomb's constant (8.99 × 109 Nm2/C2). To find the magnitude of the charge, we can rearrange the formula to solve for Q: Q = Vr/k.
By substituting the given values into the formula, we get Q = (6.00 × 102 V × 14.9 m) / (8.99 × 109 Nm2/C2). This calculation results in Q = 4.03 × 10-8 C. Since the potential is positive, the charge is also positive.
Therefore, the magnitude of the charge is 4.03 × 10-8 C and its sign is positive.