If the 1,464-lb boom AB, the 246-lb cage BCD, and the 156-lb man have centers of gravity located at points $ G_1, G_2, $ and $ G_3 $ respectively, determine the resultant moment produced by all the weights about point A in kip·ft. (Assume counter-clockwise as positive.)

To determine the resultant moment produced by all the weights about point A, we need to calculate the moment of each weight and then add them together.

The moment of a weight is given by the weight multiplied by the perpendicular distance from the weight to the point about which we are calculating the moment.

Let's denote the distances as follows:
- Distance from point A to point G1 as d1
- Distance from point A to point G2 as d2
- Distance from point A to point G3 as d3

The moment produced by the boom AB is calculated as the weight of the boom (1,464 lb) multiplied by the distance d1.
The moment produced by the cage BCD is calculated as the weight of the cage (246 lb) multiplied by the distance d2.
The moment produced by the man is calculated as the weight of the man (156 lb) multiplied by the distance d3.

To find the resultant moment, we sum up these moments:
Resultant moment = Moment of boom AB + Moment of cage BCD + Moment of man

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If the 1,464-lb boom AB, the 246-lb cage BCD, and the 156-lb man have centers of gravity located at points \( G_1, G_2, \) and \( G_3 \) respectively, determine the resultant moment produced by all the weights about point A in kip·ft. (Assume counter-clockwise as positive.)

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