Answer :
Final answer:
After calculating the minimum and maximum weight per watermelon and multiplying by five, it was determined that option (e) 57.3 kg is not a possible weight for five watermelons, as it exceeds the maximum calculated limit.
Explanation:
The question provided is asking to find out which of the given weights is not possible for five watermelons, given that nine watermelons weigh between 98 kg and 103 kg. To solve this, first, we need to calculate the minimum and maximum weight of one watermelon by dividing the total weight ranges (98 kg and 103 kg) by nine. Then we'll multiply those minimum and maximum weights by five to get the weight range for five watermelons.
Minimum weight per watermelon = 98 kg / 9 ≈ 10.89 kg
Maximum weight per watermelon = 103 kg / 9 ≈ 11.44 kg
Therefore, for five watermelons:
Minimum total weight = 5 × 10.89 kg = 54.45 kg
Maximum total weight = 5 × 11.44 kg = 57.2 kg
Now, we look at the provided options and see that option (d) 56.9 kg falls within our calculated weight range for five watermelons but option (e) 57.3 kg does not. So, the weight of 5 such watermelons cannot be equal to 57.3 kg.
