High School

if car, mass 1485 kg, traveling south at 116 km/h, slows to stop in 10.25 second. what is the magnitude and direction of the net force that acted on the car?​

Answer :

Final answer:

The net force that stopped the car was 4665.9 N directed north. This was determined using Newton's second law and considering the deceleration of the car.

Explanation:

The question deals with Newton's second law, force = mass x acceleration. The car's mass (m) is given as 1485 kg, and the change in velocity (a) - deceleration - can be calculated from the change in speed, 116 km/h to 0 km/h, over the time period of 10.25 seconds.

First, the speed needs to be converted to meters per second by multiplying by 0.27778 (116 km/h = 32.2 m/s). The change in velocity (acceleration) is this speed divided by the time period: 32.2 m/s / 10.25s = -3.14 m/s² - it's negative because it's deceleration. Then, we can compute the force using F = m x a: F = 1485 kg x -3.14 m/s² = -4665.9 N. The direction is north, opposite to the direction of travel.

Learn more about Newton's Second Law here:

https://brainly.com/question/18769451

#SPJ11