High School

If a 1500 kg car comes to a stop without skidding, the car's brakes do 10,000 J of work to stop the car. What was the car's velocity when the brakes were initially applied?

Answer :

The car's velocity when the brakes were initially applied -26.67. The negative sign indicates that the initial velocity is in the opposite direction to the force applied by the brakes.

To find the initial velocity of the car before the brakes were applied, we can use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy.

The work done by the brakes is converted into the kinetic energy of the car.

[tex]W = ½m(V_f^2-V_i^2)\\10000 = ½ * 1500 * (0^2 - v_i^2)\\10000 = ½ * 1500 * (-v_i^2)\\10000 = -750/2 * v_i^2\\10000 = -375 * v_i^2\\-10000/375 = v_i^2\\v_i^2=−26.67[/tex]

A negative value is obtained by computers the initial velocity from the brakes' work, which suggests that there is a discrepancy in the way the problem was set up or solved. This implies that other factors, like friction, might be at play or that the brakes alone may not be sufficient to bring the car to a complete stop.

Complete Question:

if a 1500 kg car vomes to a stop without skidding. the cars brakes do 10000j of work to shop the car. what was the cars velocity when the brakes were initally appiled?