Answer :
If 97.5 mol of an ideal gas occupies 36.5 L at 463 K, then the pressure of the gas is 101.49 atm.
We know that the Ideal Gas Law states that
PV = nRT .... (i)
where P ⇒ Pressure
V ⇒ Volume
n ⇒ Number of moles
R ⇒ Ideal Gas Constant
T ⇒ Temperature
From the question, we know
V = 36.5 L
n = 97.5 mol
R = 0.08206 L atm mol⁻¹ K⁻¹
T = 463 K
If we put these values in equation (i), we get
P × 36.5 L = 97.5 mol × 0.08206 L atm mol⁻¹ K⁻¹ × 463 K
P = 97.5 mol × 0.08206 L atm mol⁻¹ K⁻¹ × 463 K / 36.5 L
P = 101.49 atm
Hence, if 97.5 mol of an ideal gas occupies 36.5 L at 463 K, then the pressure of the gas is 101.49 atm.
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