Answer :
Final answer:
To calculate the volume of oxygen produced by heating 245 kg of pure KClO3 at STP, we need to determine the number of moles of KClO3 using its molar mass and then use stoichiometry to find the number of moles of O2 produced. Finally, we can use the ideal gas law to calculate the volume of oxygen.
Explanation:
To calculate the volume of oxygen produced by heating 245 kg of pure KClO3 at STP, we first need to determine the number of moles of KClO3 using its molar mass. The molar mass of KClO3 is calculated by adding the atomic weights of each element: (39 + 35.5 + (16 * 3)) g/mol = 122.5 g/mol.
Next, we calculate the number of moles of KClO3 using the formula: Moles = Mass / Molar Mass = 245000 g / 122.5 g/mol = 2000 mol.
Since the balanced equation for the decomposition of KClO3 is 2 KClO3 -> 2 KCl + 3 O2, we can see that for every 2 moles of KClO3, we get 3 moles of O2. Therefore, the number of moles of O2 produced is (2000 mol KClO3 * 3 mol O2) / 2 mol KClO3 = 3000 mol O2.
Finally, we use the ideal gas law to calculate the volume of oxygen at STP. We know that 1 mole of any ideal gas at STP occupies 22.4 L, so the volume of oxygen produced is: Volume = Moles * 22.4 L/mol = 3000 mol O2 * 22.4 L/mol = 67,200 L.
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