Answer :
Final answer:
The percentage composition of A in the obtained sample, as calculated using the given parameters of height and width of peaks from a gas chromatogram, is approximately 29%.
Explanation:
The subject of this question deals with the concept of Gas Chromatography and asks us to determine the percentage composition of a component 'A' obtained in the sample using given parameters— peak heights and peak widths at half height. Hence, this is related to Chemistry, specifically Analytical Chemistry.
Firstly, we need to understand that the area of a peak in a gas chromatogram is proportional to the quantity of that component in the sample. The area of the peak can be calculated approximately as the height of the peak times the width at half height. Therefore, the areas of peaks A, B, and C can be calculated as follows:
- Area of A = 25.1 mm * 4.6 mm = 115.46 mm²,
- Area of B = 14.5 mm * 4.4 mm =63.8 mm²,
- Area of C = 37.1 mm * 5.9 mm = 218.89 mm².
The total area corresponding to the entire sample will be the sum of these areas, which gives us 398.15 mm². Then, we can find the percentage composition of A in the sample by dividing the area of A by the total area, and multiplying by 100:
Percentage of A = (115.46 mm² / 398.15 mm²) * 100 = 28.98% approximately
So, the percentage composition of A in the sample is about 29%.
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Answer: Percentage Compositon Of A in the sample= 28.99%
Explanation:
First we calculate the Peak area.
Because each peak is consdered like a triangle in a Chromatogram, The Area of the peak is calculated as = height x half height of the width
Area of Pea A= 25.1 mm X 4.6mm=115.46mm2
Area of Peak B= 14.5mm x 4.4mm=63.8mm2
Area of PeaK C= 37.1mm x5.9mm =218.89mm2
Total Peak Area= 398.15mm2
Percentage Area of Peak A = Area of Peak A/Total Peak Area x 100
= 115.46 / 398.15 x 100
=0.2899 x 100
=28.99%
Percentage Compositon Of A = 28.99%
