High School

If 38.8 L of [tex]N_2[/tex] at 26.3°C and 734 torr is heated to 151°C and compressed to 1.46 L, what is the new pressure in torr?

Enter your answer in scientific notation: [tex] \text{___} \times 10^ \text{___}[/tex] torr.

Answer :

Final answer:

The new pressure of the gas is approximately 6.23 x 104 torr.

Explanation:

To calculate the new pressure, we can use the combined gas law:

P1V1/T1 = P2V2/T2

Where:

  • P1 is the initial pressure (734 torr)
  • V1 is the initial volume (38.8 L)
  • T1 is the initial temperature in Kelvin (26.3°C + 273.15 = 299.45 K)
  • P2 is the final pressure (unknown)
  • V2 is the final volume (1.46 L)
  • T2 is the final temperature in Kelvin (151°C + 273.15 = 424.15 K)

Substituting the given values into the equation:

(734 torr)(38.8 L)/(299.45 K) = (P2)(1.46 L)/(424.15 K)

Simplifying the equation:

(734 torr)(38.8 L)(424.15 K) = (P2)(1.46 L)(299.45 K)

Solving for P2:

P2 = (734 torr)(38.8 L)(424.15 K) / (1.46 L)(299.45 K)

Calculating the value:

P2 ≈ 6.23 x 104 torr

Learn more about calculating the new pressure of a gas when heated and compressed here:

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