College

Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ If 35.8 grams of Zn is reacted with 12.9 grams of O\(_2\), which reactant is limiting?

Answer :

The limiting reactant for the reaction of 35.8 grams of zinc, Zn and 12.9 grams of oxygen, O₂ is zinc, Zn

How to determine the limiting reactant for the reaction?

The following were obtained from the question:

  • Mass of Zn before reaction = 35.8 grams
  • Mass of O₂ before reaction = 12.9 grams
  • Limiting reactant =?

The limiting reactant for the reaction of 35.8 grams of zinc, Zn and 12.9 grams of oxygen, O₂ is determined as follow:

2Zn + O₂ -> 2ZnO

  • Molar mass of Zn = 65.38 g/mol
  • Mass of Zn from the balanced equation = 2 × 65.38 = 126.76 g
  • Molar mass of O₂ = 32 g/mol
  • Mass of O₂ from the balanced equation = 1 × 32 = 32 g

From the balanced equation above,

126.76 g of zinc, Zn reacted with 32 g of oxygen, O₂

Therefore,

35.8 g of zinc, Zn will react with = (35.8 × 32) / 126.76 = 9.04 g of oxygen, O₂

Now, we can see from the above that only 9.04 g of oxygen, O₂ took part in the reaction.

Thus, we can conclude that the limiting reactant is zinc, Zn

Learn more about limiting reactant:

https://brainly.com/question/11587316

#SPJ1

Other Questions