College

I need more problems that look like this one:

Paul bought 3 \(\frac{1}{3}\) pounds of bananas and apples. If he bought 1 \(\frac{4}{5}\) pounds of apples, how many pounds of bananas did he buy?

Answer :

Paul bought 1 8/15 pounds of bananas. This is obtained by subtracting 1 4/5 pounds of apples from the total weight of 3 1/3 pounds.

To find out how many pounds of bananas Paul bought, we need to subtract the pounds of apples he bought from the total weight of 3 1/3 pounds.

Given:

Total weight of bananas and apples = 3 1/3 pounds

Weight of apples = 1 4/5 pounds

First, we need to convert the mixed numbers to improper fractions for easier subtraction:

Total weight = 3 + 1/3 = 10/3 pounds

Weight of apples = 1 + 4/5 = 9/5 pounds

Now, let's subtract the weight of apples from the total weight:

[tex]\[ \text{Weight of bananas} = \text{Total weight} - \text{Weight of apples} \][/tex]

[tex]\[ = \frac{10}{3} - \frac{9}{5} \][/tex]

To subtract fractions with different denominators, we need to find a common denominator, which in this case is 15:

[tex]\[ = \frac{10 \times 5}{3 \times 5} - \frac{9 \times 3}{5 \times 3} \][/tex]

[tex]\[ = \frac{50}{15} - \frac{27}{15} \][/tex]

Now, subtract the numerators:

[tex]\[ = \frac{50 - 27}{15} \][/tex]

[tex]\[ = \frac{23}{15} \][/tex]

So, Paul bought [tex]\( \frac{23}{15} \)[/tex]pounds of bananas.

Now, let's express this as a mixed number:

[tex]\[ \frac{23}{15} = 1 \frac{8}{15} \][/tex]

Therefore, Paul bought 1 8/15 pounds of bananas.

The Correct question is:

Paul bought 3 1/3 pounds of bananas and apples. If he bought pounds of apples, 1 4/5 now many pounds of bananas did he buy?