High School

How much water would form if 4.8 grams of hydrogen reacted with 38.4 grams of oxygen?

Answer :

hydrogen reacts with oxygen to form water based on the following equation:
2H2 + O2 ..............> 2H2O
This means that 4 grams of hydrogen are required to react with 32 grams of oxygen to release 36 grams of water.
We need to calculate how munch oxygen is needed to react with 4.8 grams of hydrogen. We can do this using cross multiplication as follows:
amount of oxygen = (4.8x32) / 4 = 38.4 grams

This means that we have no limiting reagent here and both reactants will completely react.
We know that 4 grams of hydrogen are required to produce 36 grams of water. Therefore:
amount of water produced from 4.8 grams of hydrogen = (4.8 x 36) /4 = 43.2 grams

Final answer:

According to the given reaction equation, 4.8 grams of hydrogen would react with 38.4 grams of oxygen to produce 43.2 grams of water.

Explanation:

In this reaction, 2 moles of hydrogen gas (H2) react with 1 mole of oxygen gas (O2) to form 2 moles of water (H2O). To determine the amount of water formed, we need to convert the given masses of hydrogen and oxygen to moles and then use the mole ratio to calculate the moles of water produced.

Atomic mass of hydrogen (H) = 1 g/mol

Atomic mass of oxygen (O) = 16 g/mol
Number of moles of hydrogen (H2) = 4.8 g / 2 g/mol = 2.4 moles

Number of moles of oxygen (O2) = 38.4 g / 32 g/mol = 1.2 moles

According to the balanced equation, 2 moles of hydrogen react with 1 mole of oxygen to form 2 moles of water. Therefore, the number of moles of water formed is also 2.4 moles.

To find the mass of water formed, we can use the molar mass of water:

Molar mass of water (H2O) = 18 g/mol

Mass of water formed = 2.4 moles × 18 g/mol = 43.2 g

Therefore, 43.2 grams of water would form if 4.8 grams of hydrogen reacted with 38.4 grams of oxygen.

Learn more about Water formation in a chemical reaction here:

https://brainly.com/question/14796831

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