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------------------------------------------------ How much water should be added to 10 mL of 3.00 M HCl(aq) in order to dilute it to a 2.00 M solution of HCl(aq)?

Answer :

M1V1 = M2V2

Plug in the given values and solve for V2:

(3.00 M)(10 mL) = (2.00 M)(V2)

V2 = 15 mL

The question asks how much water should be added to the original solution, so subtract by the original amount, V1:

15 - 10 = 5 mL

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