College

How much heat is required to melt 39.4 g of ice at [tex](0^\circ C)[/tex]?

The heat of fusion for water is 6.02 kJ/mol.

Answer :

Specific heat capacity of a substance is the amount of heat required to raise the temperature by one degree Celsius of one gram of a substance. Therefore, 13.12KJ of heat is required to melt 39.4 g of ice at (0 ∘C ).

What is Enthalpy?

Enthalpy term is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, Enthalpy is directly proportional to specific heat capacity of a substances.

Mathematically,

q = n ×ΔH

where

q = amount of heat= ?

n = no of moles

ΔH = enthalpy ( 6.02 kJ/ mol)

n = w / M.M

w = given mass =39.4g

M.M = molar mass ( molar mass of water)=18g/mol

n =39.4/ 18

=2.18

Substituting all the given values, we get

q = n ×ΔH

= 2.18 ×6.02

= 12.401 kJ

=13.12KJ

Therefore, 13.12KJ of heat is required to melt 39.4 g of ice at (0 ∘C ).

To know more about enthalpy, here:

https://brainly.com/question/24170335

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