Answer :
Final answer:
The amount of heat evolved or absorbed when a 38.1 g sample of ethanol (specific heat = 2.46 J/(gK)) cools from 89.6°C to 77°C is approximately 1196 J.
Explanation:
To find the heat evolved or absorbed when a 38.1 g sample of ethanol cools from 89.6°C to 77°C, we use the formula q = mcΔT, where q is the heat, m is the mass, c is the specific heat, and ΔT is the change in temperature.
Plugging in the given values:
- Mass = 38.1g
- Specific heat = 2.46 J/(gK)
- Change in temperature = 89.6°C - 77°C = 12.6°C
Using the formula,
q = (38.1g)(2.46 J/(gK))(12.6°C)
= 1195.89 J
Thus, the heat evolved or absorbed is approximately 1196 J.
Learn more about heat transfer here:
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