Answer :
Answer: a 165 kg roller coaster car has 691,600 J of gravitational potential energy when it is at the top of a hill 42 meters above the ground.
Explanation:
Gravitational potential energy (GPE) is the energy an object possesses due to its position in a gravitational field. The formula for GPE is GPE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height above a reference point.
Given that the mass of the roller coaster car is 165 kg and it's at the top of a hill 42 meters above the ground, we can substitute these values into the formula:
GPE = 165 kg * 9.8 m/s^2 * 42 m
GPE = 691,600 J (joules)
So a 165 kg roller coaster car has 691,600 J of gravitational potential energy when it is at the top of a hill 42 meters above the ground.
Final answer:
The gravitational potential energy of the roller coaster car is calculated using the formula PE = m * g * h, with the values given in the problem. After calculation, it is found that the potential energy of the roller coaster at the top of the 42m high hill is approximately 68,086 Joules.
Explanation:
The question asks for the gravitational potential energy of a roller coaster car when it is at the top of a hill. The formula for calculating gravitational potential energy is:
Potential Energy (PE) = mass (m) * gravity (g) * height (h)
In this case, the mass of the roller coaster car is 165 kg, the acceleration due to gravity is approximately 9.81 m/s², and the height of the hill is 42 meters. Therefore, we can calculate the potential energy using these values as follows:
PE = 165 kg * 9.81 m/s² * 42 m
After calculating, we can find that the gravitational potential energy of the roller coaster at the top of the hill is approximately 68,086 Joules (rounded to the nearest whole number).
Learn more about Gravitational Potential Energy here:
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