Answer :
First, convert the volume from milliliters to liters. Since there are 1000 mL in 1 L, the volume in liters is given by
[tex]$$
\text{Volume in L} = \frac{7000 \text{ mL}}{1000} = 7 \text{ L}.
$$[/tex]
Next, use the definition of molarity: a 0.6 M solution contains 0.6 moles of solute per liter of solution. The number of moles ([tex]$n$[/tex]) of the solute is calculated as
[tex]$$
n = \text{molarity} \times \text{volume in L} = 0.6 \times 7.
$$[/tex]
Thus, the number of moles is
[tex]$$
n = 4.2 \text{ moles}.
$$[/tex]
So, there are [tex]$4.2$[/tex] moles of [tex]$\text{Ba(ClO}_4\text{)}_2$[/tex] in 7000 mL of a 0.6 M solution.
[tex]$$
\text{Volume in L} = \frac{7000 \text{ mL}}{1000} = 7 \text{ L}.
$$[/tex]
Next, use the definition of molarity: a 0.6 M solution contains 0.6 moles of solute per liter of solution. The number of moles ([tex]$n$[/tex]) of the solute is calculated as
[tex]$$
n = \text{molarity} \times \text{volume in L} = 0.6 \times 7.
$$[/tex]
Thus, the number of moles is
[tex]$$
n = 4.2 \text{ moles}.
$$[/tex]
So, there are [tex]$4.2$[/tex] moles of [tex]$\text{Ba(ClO}_4\text{)}_2$[/tex] in 7000 mL of a 0.6 M solution.
