Answer :
Final answer:
The standard enthalpy of reaction can be calculated using the formula: ΔH = q / n, where ΔH is the change in enthalpy, q is the heat released or absorbed, and n is the number of moles of the substance involved in the reaction. In this case, we have 3.14 kJ of heat produced when 1.34 g of zinc reacts. Therefore, the enthalpy change per mole of zinc reacting is 153.17 kJ/mol.
Explanation:
The standard enthalpy of reaction can be calculated using the formula:
ΔH = q / n
where:
- ΔH is the change in enthalpy
- q is the heat released or absorbed
- n is the number of moles of the substance involved in the reaction
In this case, we have 3.14 kJ of heat produced when 1.34 g of zinc reacts. To determine the enthalpy change per mole of zinc reacting, we need to calculate the number of moles of zinc involved in the reaction. The molar mass of zinc is 65.38 g/mol, so:
n = mass / molar mass = 1.34 g / 65.38 g/mol = 0.0205 mol
Now we can calculate the standard enthalpy of reaction:
ΔH = q / n = 3.14 kJ / 0.0205 mol = 153.17 kJ/mol
Therefore, the enthalpy change per mole of zinc reacting is 153.17 kJ/mol.
