How many moles of each product are produced when 8.00 moles of potassium chlorate are heated and decompose into potassium chloride and oxygen gas?

The unbalanced equation options:

A. 8.00 moles of potassium chloride and 8.00 moles of oxygen gas
B. 4.00 moles of potassium chloride and 4.00 moles of oxygen gas
C. 8.00 moles of potassium chloride and 4.00 moles of oxygen gas
D. 4.00 moles of potassium chloride and 8.00 moles of oxygen gas

When 8.00 moles of potassium chlorate (KClO3) decompose, it produces 8.00 moles of potassium chloride (KCl) and 12.00 moles of oxygen (O2), not 4.00 as listed in the options. None of the provided options is correct. The correct answer is 8.00 moles of potassium chloride and 12.00 moles of oxygen gas.

The decomposition of potassium chlorate (KClO3) into potassium chloride (KCl) and oxygen gas (O2) is described by the balanced chemical equation: 2 KClO3(s) right arrow 2 KCl(s) + 3 O2(g)

According to the stoichiometry of this decomposition reaction, 2 moles of potassium chlorate produce 2 moles of potassium chloride and 3 moles of oxygen gas. Therefore, if 8.00 moles of potassium chlorate are heated, the products formed would be 8.00 moles of potassium chloride and 12.00 moles of oxygen gas. However, since this option is not provided in the choices. None of the provided options is correct. The correct answer is 8.00 moles of potassium chloride and 12.00 moles of oxygen gas.