High School

Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ How many milliliters of a 0.330 M KOH solution contain [tex]1.69 \times 10^{-2} \text{ mol}[/tex] of KOH?

Answer :

51.2 mL of the 0.330 mm KOH solution contains 1.69×10−2 mol of KOH. we can use the formula:

Volume = (amount of solute) / (molarity)

To calculate the volume of the solution containing a given number of moles of solute, we can use the formula:

Volume = (amount of solute) / (molarity)

Here, the molarity of the KOH solution is 0.330 mm or 0.330 × 10^-3 mol/mL. The amount of KOH in 1.69×10−2 mol is:

Amount of solute = 1.69×10−2 mol

Putting the values in the formula, we get:

Volume = (1.69×10−2 mol) / (0.330 × 10^-3 mol/mL)

Volume = 51.2 mL

Therefore, 51.2 mL of the 0.330 mm KOH solution contains 1.69×10−2 mol of KOH.

To learn more about Molarity click here

https://brainly.com/question/8732513

#SPJ11

Other Questions