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------------------------------------------------ How many mEq of Ca\(^{2+}\) are present in a solution that also contains:

- 75 mEq Na\(^+\)
- 83 mEq K\(^+\)
- 35 mEq HCO\(_3^−\)
- 153 mEq Cl\(^−\)

Answer :

To calculate the milli equivalents (mEq) of Ca2+ present in the solution, we need to determine the number of moles of Ca2+ and then convert it to milli equivalents using its valence.

Given the mEq values of various ions in the solution:

- Na+: 75 mEq

- K+: 83 mEq

- HCO3-: 35 mEq

- Cl-: 153 mEq

We need to find the mEq of Ca2+.

1. Determine the mEq of Cl- ions: Since Cl- has a 1- charge, the mEq of Cl- is equal to its mEq value, which is 153 mEq.

2. Determine the mEq of HCO3- ions: Since HCO3- also has a 1- charge, the mEq of HCO3- is equal to its mEq value, which is 35 mEq.

3. Calculate the total charge contributed by Na+, K+, Cl-, and HCO3- ions:

Total charge = (75 mEq Na+ × 1+) + (83 mEq K+ × 1+) + (153 mEq Cl- × (-1)) + (35 mEq HCO3- × (-1))

Total charge = 75 + 83 - 153 - 35

Total charge = -30

4. Since the solution is electrically neutral, the total charge contributed by all ions must be balanced by the positive charge of Ca2+ ions.

5. Determine the mEq of Ca2+ ions:

Total charge contributed by Ca2+ ions = Total charge (from step 3) = -30

Since Ca2+ has a 2+ charge, the mEq of Ca2+ is half of the total charge:

mEq of Ca2+ = -30 / 2 = -15 mEq

However, it is important to note that negative mEq values are not meaningful in this context. It suggests an error in the data or calculations. Double-checking the given mEq values or the provided information would necessary to provide a valid answer.

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