High School

How many grams of sodium fluoride (NaF) are dissolved in 3.75 L of a 1.55 M solution?

- Molar Mass of Na: 22.99 g/mol
- Molar Mass of F: 19.00 g/mol

Answer :

164.22 grams of sodium fluoride are dissolved in 3.75 L of a 1.55 M solution.

To find the number of grams of sodium fluoride (NaF) dissolved in 3.75 L of a 1.55 M solution, you can use the formula:

molarity (M) x volume (L) x molar mass (g/mol) = mass (g)

Sodium fluoride (NaF) has the following molar mass:

22.99 g/mol (Na) + 19.00 g/mol (F) = 41.99 g/mol

So the mass of sodium fluoride dissolved in 3.75 L of a 1.55 M solution is:

mass (g) = 1.55 M x 3.75 L x 41.99 g/mol = 164.22 g

Therefore, 164.22 grams of sodium fluoride are dissolved in 3.75 L of a 1.55 M solution.

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