High School

How fast would a 67 kg person have to run to have that amount of energy? Express your answer with the appropriate units.

Answer :

The 67 kg person has to run at the speed of [tex]\sqrt{((2 \times KE) / 67)}[/tex] m/s to have that amount of energy.

To calculate the kinetic energy (KE) of a person running, we can use the formula

KE = [tex]0.5 \times m \times v^2[/tex]

where m is the mass (67 kg) and v is the velocity in meters per second (m/s).

First, we need to determine the desired amount of energy, which is not provided in the question.
Obtain the desired energy value (in joules, J) you want the person to have while running.

Plug the mass (67 kg) and the desired energy value into the KE formula: [tex]KE = 0.5 \times 67 \times v^2[/tex].

Rearrange the formula to isolate v:

[tex]v^2 = (2 \times KE) / 67[/tex] m/s

Calculate v by taking the square root

[tex]v = \sqrt {(2 \times KE) / 67)}[/tex] m/s

The calculated value of v will be the velocity in meters per second (m/s) required for the person to have the desired amount of energy while running.
Remember to replace "KE" with the desired energy value in joules, and you will get the velocity (in m/s) needed for a 67 kg person to have that amount of energy.

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