Answer :
Final answer:
To find how many grams of sodium chloride are needed for 950 mg of sodium, calculate moles of NaCl, moles of ions present, and the molality of ions. The correct answer is 2.44 grams of NaCl.
Explanation:
The formula mass of NaCl is 58.44 g/mol. To determine the grams of NaCl needed for 950 mg of Na, we first calculate the moles of NaCl, then find the moles of ions present, and finally determine the molality of the ions in the solution.
The correct answer is A) 2.44 grams of NaCl are needed to have 950 mg of Na present, considering the given concentration of sodium in sodium chloride.
Final answer:
To find out how many grams of sodium chloride are needed to have 950 mg of Na present, we can set up a proportion using the percentage composition of sodium chloride. The correct answer is 2.44 grams.
Explanation:
To find out how many grams of sodium chloride are needed to have 950 mg of Na present, we can use the given information that sodium chloride is 39.0% sodium by mass. This means that for every gram of sodium chloride, there is 0.39 grams of sodium. We can set up a proportion to solve for the grams of sodium chloride needed:
0.39 grams of sodium / 1 gram of sodium chloride = 0.95 grams of sodium / x grams of sodium chloride
Cross multiplying, we get:
0.39x = 0.95 * 1
x = 0.95 / 0.39 = 2.44 grams of sodium chloride
Therefore, the correct answer is A) 2.44 grams.
Learn more about Percentage Composition here:
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