High School

Given Information:

- Calls arrive at a rate of 14 per hour \((\lambda = 14)\).
- The sales rep processes calls at an average rate of 4 minutes per call. Since there are 60 minutes in an hour, the service rate is \(\mu = \frac{60}{4} = 15\) calls per hour.

Which statement is not true?

A. M/M/s model is suitable to analyze this problem.
B. \(\lambda = 14\)
C. \(\mu = 4\)
D. M/M/1 model can be used to analyze the problem.

Answer :

The incorrect statement is C. μ = 4 because the service rate (μ) is actually 15 calls per hour, not 4. The other statements about the suitability of the M/M/s and M/M/1 models and the arrival rate λ being 14 are correct.

We are asked to identify which statement is not true given the following information about call arrivals and processing rates:

Calls arrive at a rate of 14 per hour (λ = 14).

The sales rep processes calls at an average rate of 4 minutes per call.

Since there are 60 minutes in an hour, the service rate is μ = 60 / 4 = 15 calls per hour.

The call arrival rate λ is indeed 14.

The service rate μ is calculated as 15 calls per hour, which is correct given the average processing time of 4 minutes per call (60/4).

The incorrect statement is:

C. μ = 4 - This is false because μ is the average service rate, which is 15 calls per hour as we calculated above, not 4.

Regarding the queuing models:

An M/M/s model is suitable to analyze this problem where 's' represents the number of service channels (in this case, it is '1'). An M/M/1 model should be appropriate since the system has a single service channel (the sales rep), and the call arrivals and service times both follow an exponential distribution.