Answer :
The sum of valence electrons is 4 + 21 + 5 = 30. However, we must consider the "+1" charge, indicating the loss of one electron. Subtracting one from the total, we have a final count of 30 - 1 = 29 valence electrons for CF3NH3+.
Carbon (C) is in group 4, so it has 4 valence electrons. There are three fluorine (F) atoms, each contributing 7 valence electrons (since fluorine is in group 7). Nitrogen (N) is in group 5, so it has 5 valence electrons. Adding up the contributions, we have:
C: 4 valence electrons
F: 3 x 7 = 21 valence electrons
N: 5 valence electrons
The total sum of valence electrons is 4 + 21 + 5 = 30. However, we must consider the "+1" charge, indicating the loss of one electron. Subtracting one from the total, we have a final count of 30 - 1 = 29 valence electrons for CF3NH3+.
The number of valence electrons for CF3NH3+ can be determined by summing the valence electrons contributed by each element in the molecule.
In this case, carbon (C) and nitrogen (N) each contribute their group number of valence electrons, while fluorine (F) contributes one valence electron.
Additionally, the "+1" charge indicates the loss of one electron. Therefore, to find the total number of valence electrons, we add the valence electrons from each element and subtract one due to the positive charge.
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