High School

For a buck-boost converter operated at a switching frequency of 10 kHz, compute the output voltage and output power if:

- Load resistance is 3 ohms
- Input voltage is 13.6 V
- Duty cycles are 0.3, 0.5, and 0.9

For a buck converter with an ON time of 12 µs, where:

- Battery voltage is 14.2 V
- Required output voltage is 6.3 V

Find:

a) Switching frequency
b) OFF time

Answer :

a) The switching frequency of the buck-boost converter is 10 kHz.

b) The OFF time of the buck converter with an ON time of 12 µs and a required output voltage of 6.3 V is 88 µs.

a) To compute the switching frequency for the buck-boost converter operated at 10 kHz, we use the formula:

Switching frequency = 1 / switching period

Given that the switching frequency is 10 kHz, we can calculate the switching period as:

Switching period = 1 / (10 kHz) = 1 / (10,000 Hz) = 100 µs

Therefore, the switching frequency of the buck-boost converter is 10 kHz.

b) For the buck converter with an ON time of 12 µs and a required output voltage of 6.3 V, we can find the OFF time using the formula:

OFF time = Switching period - ON time

Given that the battery voltage is 14.2 V and the required output voltage is 6.3 V, we can calculate the OFF time as:

OFF time = Switching period - ON time = 100 µs - 12 µs = 88 µs

Therefore, the OFF time of the buck converter is 88 µs.

Learn more about switching frequencies at

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