High School

Fill in the blanks in the below statement. Kinetic energy of a 25000−kg truck moving at 32 m/s is ×10 6 joules, and the kinetic energy of a 84−kg astronaut moving in orbit at 6800 m/s is ×10 9 joules. Comparing kinetic energies of the two of them, has greater kinetic energy.

Answer :

The kinetic energy of an object is given by the formula KE = 1/2 * m * v^2, where KE represents the kinetic energy, m represents the mass of the object, and v represents the velocity of the object.

Let's calculate the kinetic energy of the 25000-kg truck first.

Given:
Mass of the truck (m) = 25000 kg
Velocity of the truck (v) = 32 m/s

Plugging in these values into the formula, we get:
KE_truck = 1/2 * 25000 kg * (32 m/s)^2

Simplifying the equation, we have:
KE_truck = 1/2 * 25000 kg * 1024 m^2/s^2
KE_truck = 12800000 kg m^2/s^2

So, the kinetic energy of the truck is 12,800,000 joules.

Now, let's calculate the kinetic energy of the 84-kg astronaut in orbit.

Given:
Mass of the astronaut (m) = 84 kg
Velocity of the astronaut (v) = 6800 m/s

Plugging in these values into the formula, we get:
KE_astronaut = 1/2 * 84 kg * (6800 m/s)^2

Simplifying the equation, we have:
KE_astronaut = 1/2 * 84 kg * 46240000 m^2/s^2
KE_astronaut = 1949760000 kg m^2/s^2

So, the kinetic energy of the astronaut is 1,949,760,000 joules.

Comparing the kinetic energies of the two:
KE_truck = 12,800,000 joules
KE_astronaut = 1,949,760,000 joules

Since 1,949,760,000 joules is greater than 12,800,000 joules, the astronaut has a greater kinetic energy than the truck.

To know more about kinetic energy :

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