Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ Find three consecutive integers such that the sum of the second and triple the third is 193 more than the first.

To solve the problem, one can form an algebraic equation based on the provided conditions and solve for 'n'. The three consecutive integers for this problem are 94, 95, and 96.

Explanation:

This question is a type of algebraic word problem that involves consecutive integers. In this case, we need to find three consecutive integers so that the sum of the second integer and triple the third integer equals a value that is 193 more than the first integer.

To solve this, let's define the first integer as 'n'. Since the integers are consecutive, the second and third ones can be defined as 'n+1' and 'n+2', respectively.

According to the problem, the sum of the second integer and three times the third integer is 193 more than the first. This forms our equation: (n+1) + 3(n+2) = n + 193.

Solving the equation gives us n = 94. Therefore, the three consecutive integers are 94, 95, and 96.

Learn more about Consecutive Integers here:

https://brainly.com/question/35707212

#SPJ11