Find the equivalent capacitance between points a and b for the group of capacitors connected as shown in the figure above.

Take [tex]C_1 = 8.00 \, \mu\text{F}[/tex], [tex]C_2 = 14.0 \, \mu\text{F}[/tex], and [tex]C_3 = 4.00 \, \mu\text{F}[/tex].

To find the equivalent capacitance between points a and b, we can use the formula for capacitors connected in parallel. When capacitors are connected in parallel, the equivalent capacitance is simply the sum of the individual capacitances.

In this case, C1 = 8.00 µF, C2 = 14.0 µF, and C3 = 4.00 µF. Therefore, the equivalent capacitance between points a and b is C = C1 + C2 + C3 = 8.00 µF + 14.0 µF + 4.00 µF = 26.0 µF.

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Find the equivalent capacitance between points a and b for the group of capacitors connected as shown in the figure above. Take [tex]C_1 = 8.00 \, \mu\text{F}[/tex], [tex]C_2 = 14.0 \, \mu\text{F}[/tex], and [tex]C_3 = 4.00 \, \mu\text{F}[/tex].

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Find the equivalent capacitance between points a and b for the group of capacitors connected as shown in the figure above.

Take [tex]C_1 = 8.00 \, \mu\text{F}[/tex], [tex]C_2 = 14.0 \, \mu\text{F}[/tex], and [tex]C_3 = 4.00 \, \mu\text{F}[/tex].