High School

Find the area under the function [tex]f(x) = 2x^{1/2} + 7[/tex] between [tex]x = 4[/tex] and [tex]x = 16[/tex].

Answer :

The area under the function f(x) = 2[tex]x^{(1/2)[/tex] + 7 between 4 and 16 is 476/3 square units.

Here's how to find the area under the curve:

1. Set up the Definite Integral

The area under the curve f(x) = 2[tex]x^{(1/2)[/tex] + 7 between x = 4 and x = 16 is represented by the definite integral:

∫₄¹⁶ (2[tex]x^{(1/2)[/tex] + 7) dx

2. Evaluate the Integral

Find the antiderivative:

∫(2[tex]x^{(1/2)[/tex] + 7) dx = (4/3)[tex]x^{(3/2)[/tex] + 7x + C

Evaluate at the limits of integration:

[(4/3)[tex](16)^{(3/2)[/tex] + 7(16)] - [(4/3)[tex](4)^{(3/2)[/tex] + 7(4)]

Simplify:

[(4/3)(64) + 112] - [(4/3)(8) + 28]

= (256/3 + 112) - (32/3 + 28)

= (592/3) - (116/3)

= 476/3.