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A piece of carpet can contain millions of dust mites. If dust mites of the size below stood end-to-end to make a line 1.25×102 m long, how many dust mites would there be?

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Answer :

Using proportions, it is found that there would be 500,000 mites.

  • This question is solved by proportions, using a rule of three.
  • Each dust mite has a length of [tex]2.5 \times 10^{-4}[/tex] m. How many dust mites could there be in a line of [tex]1.25 \times 10^2[/tex] m long?

The rule of three is:

1 dust mite - [tex]2.5 \times 10^{-4}[/tex] m.

x dust mites - [tex]1.25 \times 10^2[/tex] m

Applying cross multiplication:

[tex]2.5 \times 10^{-4}x = 1.25 \times 10^2[/tex]

[tex]x = \frac{1.25 \times 10^2}{2.5 \times 10^{-4}}[/tex]

[tex]x = 500000[/tex]

There would be 500,000 mites.

A similar problem is given at https://brainly.com/question/24372153