Answer :
When adding the numbers 172 and 264, it becomes necessary to regroup because the sum of certain digits exceeds 9. Here is a detailed explanation:
1. Start with the Ones Place:
- Add the digits in the ones place: 2 (from 172) + 4 (from 264) = 6.
- Since the sum is 6, which is less than 10, there is no need for regrouping in the ones place.
2. Move to the Tens Place:
- Next, add the digits in the tens place: 7 (from 172) + 6 (from 264) = 13.
- Here, the sum is 13, which is more than 9. This means we need to regroup.
- Regrouping means that 13 is separated into 10 + 3. The 3 stays in the tens place, and the 1 (from the 10) is carried over to the hundreds place.
3. Now, add the Hundreds Place:
- Add the hundreds digits along with the carry from the tens place: 1 (the carry from the tens place) + 1 (from 172) + 2 (from 264) = 4.
- The sum of the hundreds place, after including the carried over 1, is 4. This does not require further regrouping.
Therefore, regrouping is necessary here because the sum in the tens place exceeds 9, requiring a carry over to the next place value.
1. Start with the Ones Place:
- Add the digits in the ones place: 2 (from 172) + 4 (from 264) = 6.
- Since the sum is 6, which is less than 10, there is no need for regrouping in the ones place.
2. Move to the Tens Place:
- Next, add the digits in the tens place: 7 (from 172) + 6 (from 264) = 13.
- Here, the sum is 13, which is more than 9. This means we need to regroup.
- Regrouping means that 13 is separated into 10 + 3. The 3 stays in the tens place, and the 1 (from the 10) is carried over to the hundreds place.
3. Now, add the Hundreds Place:
- Add the hundreds digits along with the carry from the tens place: 1 (the carry from the tens place) + 1 (from 172) + 2 (from 264) = 4.
- The sum of the hundreds place, after including the carried over 1, is 4. This does not require further regrouping.
Therefore, regrouping is necessary here because the sum in the tens place exceeds 9, requiring a carry over to the next place value.
