College

Evaluate each algebraic expression for [tex] c = 0.6 [/tex] and [tex] d = 300 [/tex]. Remember to work from left to right.

1. [tex] d \div 20 = [/tex]

2. [tex] d \div c = [/tex]

3. [tex] 150c \div d = [/tex]

4. [tex] \frac{d}{1.5} = [/tex]

---

**Problem Solving**

Write an algebraic expression for each situation. Then evaluate the expression for the given value.

5. Mrs. Yazzie buys [tex] p [/tex] pairs of identical pants for \$95.44. Write an algebraic expression that shows the cost of each pair of pants. Determine the cost of one pair if she buys 4 pairs of pants.

6. Your storage container holds 7.5 cups of oatmeal. You are camping for [tex] d [/tex] days and plan to eat the same amount each day. Write an expression that shows how many cups of oatmeal you can eat each day. Now suppose you decide to bring a second container that holds 5 cups of raisins. Write a new expression that shows the amount of oatmeal plus raisins you can eat in days of camping. Evaluate the expression if you camp for 10 days.

---

**Write About It**

7. Describe how you would evaluate the expression [tex] \frac{a}{4} [/tex] when [tex] a = 36 [/tex]. Then evaluate the expression.

Answer :

Sure! Let's go through each part of the homework question step-by-step.

### Homework

1. Evaluate [tex]\( d \div 20 \)[/tex] for [tex]\( d = 300 \)[/tex]:

To solve this, you simply divide 300 by 20.

[tex]\[
\frac{300}{20} = 15.0
\][/tex]

So, the answer is 15.0.

2. Evaluate [tex]\( d \div c = \frac{\partial}{2} \)[/tex].

This can be interpreted as dividing [tex]\( d \)[/tex] by [tex]\( c \)[/tex] and then dividing the result by 2. Given [tex]\( d = 300 \)[/tex] and [tex]\( c = 0.6 \)[/tex]:

[tex]\[
\frac{300}{0.6} = 500
\][/tex]

Then divide by 2:

[tex]\[
\frac{500}{2} = 250.0
\][/tex]

So, the answer is 250.0.

3. Evaluate [tex]\( 150 \times c \div d \)[/tex] for [tex]\( c = 0.6 \)[/tex] and [tex]\( d = 300 \)[/tex]:

First, multiply 150 by 0.6:

[tex]\[
150 \times 0.6 = 90
\][/tex]

Then divide by 300:

[tex]\[
\frac{90}{300} = 0.3
\][/tex]

So, the answer is 0.3.

4. Evaluate [tex]\(\frac{d}{1.5} \times 25\)[/tex]:

First, divide 300 by 1.5:

[tex]\[
\frac{300}{1.5} = 200
\][/tex]

Then multiply by 25:

[tex]\[
200 \times 25 = 5000.0
\][/tex]

So, the answer is 5000.0.

### Problem Solving

5. Mrs. Yazzie buys [tex]\( p \)[/tex] pairs of identical pants for \[tex]$95.44.

To find the cost of each pair of pants, divide the total cost by the number of pairs.

If she buys 4 pairs:

\[
\frac{95.44}{4} = 23.86
\]

So, the cost per pair is \$[/tex]23.86.

6. Storage container holds 7.5 cups of oatmeal for [tex]\( d \)[/tex] days.

Expression for cups of oatmeal per day:

If camping for 10 days:

[tex]\[
\frac{7.5}{10} = 0.75
\][/tex]

So, you can eat 0.75 cups of oatmeal per day.

New scenario with 5 cups of raisins:

Combine the oatmeal and raisins:

[tex]\[
\frac{7.5 + 5}{10} = 1.25
\][/tex]

So, you can have 1.25 cups of oatmeal plus raisins each day.

7. Evaluate [tex]\(\frac{a}{4}\)[/tex] when [tex]\( a = 36 \)[/tex]:

Divide 36 by 4:

[tex]\[
\frac{36}{4} = 9.0
\][/tex]

So, the evaluation gives 9.0.

I hope this helps you understand the process! Let me know if you have any further questions.