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Eugene and Shanice each improved their yards by planting sod and geraniums. They bought their supplies from the same store.

Eugene spent $36 on 9 ft² of sod (s) and 2 geraniums (g).
Shanice spent $63 on 9 ft² of sod and 5 geraniums.

What is the solution to the system of equations? What is the cost of one ft² of sod and the cost of one geranium?

Answer :

Final answer:

The cost of one ft² of sod is $2 and the cost of one geranium is $9. This was determined by solving a system of linear equations that represent the purchases of Eugene and Shanice.

Explanation:

To solve for the cost of one ft² of sod (s) and the cost of one geranium (g), we can set up two linear equations based on the information provided:

Eugene's purchase: 36 = 9s + 2g

Shanice's purchase: 63 = 9s + 5g

Solving this system of equations:

Multiplying Eugene's equation by -1 gives us: -36 = -9s - 2g

Adding the two equations together to eliminate 's' yields: 27 = 3g

Dividing by 3 gives the cost of one geranium: g = 9

Substitute g into Eugene's equation: 36 = 9s + 2(9)

Solve for s, we get: 36 = 9s + 18

Subtract 18 from both sides: 18 = 9s

Divide by 9, we find the cost of one ft² of sod: s = 2

Therefore, one ft² of sod costs $2 and one geranium costs $9.

The cost of one ft² of sod is $2 and the cost of one geranium is $9.

What are the linear equations that represent the question?

9s + 2g = 36 equation 1

9s + 5g = 63 equation 2

What is the cost of one feet of sod and geranium?

Subtract equation 1 from equation 2:

3g = 27

g = 27 / 3

g = $9

Substitute for g in equation 1

9s + (2 x 9) = 36

9s + 18 = 36

9s = 36 - 18

9s = 18

s = 18 / 9

s = $2

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