Answer :
Ted is 14 years old and Ed is 21 years old.
Let Ted's age be represented by T. According to the problem, Ed is 7 years older than Ted, and Ed's age is also [tex]\frac{3}{2}[/tex] times Ted's age. We can set up the following equations:
- Equation 1: Ed = T + 7
- Equation 2: Ed = [tex]\frac{3}{2}[/tex]T
Since both expressions equal Ed's age, we set them equal to each other:
T + 7 = [tex]\frac{3}{2}[/tex]T
To solve for T, follow these steps:
Multiply both sides by 2 to eliminate the fraction:
2(T + 7) = 3T
Expand and simplify:
2T + 14 = 3T
Subtract 2T from both sides:
14 = T
Ted's age is 14 years.
Now, substitute T back into one of the original equations to find Ed's age:
Ed = T + 7 = 14 + 7 = 21
Therefore, Ted is 14 years old and Ed is 21 years old.
Complete question:
Ed is 7 years older than Ted. Ed's age is also [tex]\frac{3}{2}[/tex] times Ted's age. How old are Ed and Ted?
Answer:
if i'm right ted is 14 and ed is 21
Step-by-step explanation:
if ed is 7 years older than ted and is 3/2 times eds age, than we have to find out how much dose 2 represent in the equation 3/2 so we know that ed is seven years older than ted. so that means that if the equation 3/2 was 1/2, 1 would represent 7 years. (i hope your following me) so if 1 represents 7 than 2 must represent 14 and that would be the age of ted because in the equation 3/2 the 2 would represent teds age. and if the 2 represents teds age than 3 would be eds age. so 7 x 3 = 21. (this is my first time answering a question so sorry if i'm confusing)
