Answer :
Solution:
Given that:
Each pail of plaster covers 97 square feet of ceiling.
To find how many pails of plaster would you need to buy to cover the ceiling of a room with walls 14 feet long, we find the area, A, of the ceiling
To find the area, A, the formula is
[tex]\begin{gathered} A=l^2 \\ Where \\ l=14\text{ feet} \end{gathered}[/tex]Substitute 14 feet for l into the formula to find the area, A,
[tex]A=14^2=196\text{ square feet}[/tex]Where
1 pail of plaster covers 97 square feet, the number of pail of plaster that will cover the ceiling will be
[tex]\begin{gathered} For\text{ 196 square feet,} \\ =\frac{196}{97}=2.02061\text{ pails} \end{gathered}[/tex]Since, 2.02061 pails will cover the ceiling
Hence, the answer is approximately 3 pails (option A)
