Answer :
Final answer:
The ion 197/79 Au³ has 79 protons, 118 neutrons, and 76 electrons, making Option A the correct choice.
Explanation:
The ion described in the question is Au³ with a mass number of 197 and an atomic number of 79. To find the number of protons, electrons, and neutrons, we look at the atomic number, mass number, and the charge of the ion.
- Thus, the correct answer to how many protons, neutrons, and electrons are in the ion 197/79 Au³ is Option A: Protons: 79, Neutrons: 118, Electrons: 76.
The ion 197/79 Au³ has 79 protons, 118 neutrons, and 76 electrons, making option A the correct answer.
The atom represented by 197/79 Au³ indicates an ion of gold (Au). To find the number of protons, neutrons, and electrons in this ion, we look at the atomic number and mass number provided. The atomic number, which is 79 for gold, tells us there are 79 protons in the nucleus of the atom. The mass number (top number) is 197, which is the sum of the protons and neutrons. To find the number of neutrons, we subtract the number of protons (79) from the mass number (197), giving us 197 - 79 = 118 neutrons. Since this is an ion with a 3+ charge, it means there are three fewer electrons than protons. Therefore, the ion has 79 - 3 = 76 electrons.
The correct answer to how many protons, neutrons, and electrons are in the ion 197/79 Au³ is:
- Protons: 79
- Neutrons: 118
- Electrons: 76
Therefore, the correct option is A) Protons: 79, Neutrons: 118, Electrons: 76.
